(x^2)/2-2x+4=0

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Solution for (x^2)/2-2x+4=0 equation: 



(x^2)/2-2x+4=0

We multiply all the terms by the denominator


x^2-2x*2+4*2=0

We add all the numbers together, and all the variables

x^2-2x*2+8=0

Wy multiply elements

x^2-4x+8=0

a = 1; b = -4; c = +8;
Δ = b2-4ac
Δ = -42-4·1·8
Δ = -16
Delta is less than zero, so there is no solution for the equation

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